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Old 07-14-2011, 12:12 AM
ah-kay ah-kay is offline
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Join Date: Mar 2009
Location: San Diego
Posts: 3,537
1466.67' is correct but it has NOTHING to do acceleration. The terminal speed and the time taken is enough to calculate the distance travel.

The average speed is (100-0)/2 = 50mph. How it gets there is not important. 50mph for 20 sec = ((50*1760*3)/3600)*20 = 1466.67'

BTW: I assume it is mph.
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