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  #1  
Old 08-15-2008, 08:09 AM
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Electrical engineering question...

OK, this is driving me nuts... Back in HS I learned this formula but it escapes me and I can't seem to find a reference in a Googe search, etc...

What is the formula for determining resistance in a parallel circuit? I can figure out arrays that have all of the same value resistors (like speakers) in my head but what about say, 5 various values?

320 ohm
1k ohm
240 ohm
1M ohm
500K ohm



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Old 08-15-2008, 08:14 AM
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resiststance = 1/(1/320 ohm +1/1k ohm +1/240 ohm+1/1M ohm + 1/500k ohm)

For DC circuit.

AC circuits I don't recall other than there was a difference.
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Old 08-15-2008, 08:19 AM
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(r1*r2*r3*r4*r5)/(r1+r2+r3+r4+r5)
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Old 08-15-2008, 08:48 AM
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Great, thanks!
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Old 08-15-2008, 01:33 PM
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Quote:
Originally Posted by Botnst View Post
resiststance = 1/(1/320 ohm +1/1k ohm +1/240 ohm+1/1M ohm + 1/500k ohm)

For DC circuit.

AC circuits I don't recall other than there was a difference.
For a purely resistive circuit, there is no difference between AC and DC. Once you start adding in capacitance and inductance you get reactance - and that varies with the frequency of AC source.
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Old 08-15-2008, 01:38 PM
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For a purely resistive circuit, there is no difference between AC and DC. Once you start adding in capacitance and inductance you get reactance - and that varies with the frequency of AC source.
Oh yeah. Now I remember ... sort of.

Signal over wires to a speaker will vary over time in both amplitude and frequency. So you get those AC critters?

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