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TheDon 02-05-2010 10:40 PM

question
 
ok so how do I find the perimeter of a rectangle if area is given and the ratio W x L is given..

like

area=300

and the ratio is

3:1

tonkovich 02-05-2010 10:50 PM

Quote:

Originally Posted by TheDon (Post 2399631)
ok so how do I find the perimeter of a rectangle if area is given and the ratio W x L is given..

like

area=300

and the ratio is

3:1

let x = L

let 3x = W

L x W -=area , so

x X 3x = 300

3x squared = 300

therefore

x squared = 100

therefore

x=10

therefore L=10 W=30

therefore L+W+L+W = perimeter

so 80 = perimeter

(i think :D)

Brian Carlton 02-05-2010 10:53 PM

(3X)(X)=300

3X^2=300

X^2=100

X=10


Rectangle is 30 x 10.

Craig 02-05-2010 10:55 PM

L = 3W

P = 2L+2W = 6W + 2W = 8W

A = L*W = 3W*W = 3W^2

If A=300, W=10, L=30, P=80

Craig 02-05-2010 10:57 PM

Great minds....

TheDon 02-05-2010 10:59 PM

im too frigin tired.. im dealing with damn infinite loops and logical errors and cant think

Craig 02-05-2010 11:01 PM

Quote:

Originally Posted by TheDon (Post 2399644)
im too frigin tired.. im dealing with damn infinite loops and logical errors and cant think

Get a couple of hours of sleep and work while you're awake.

TheDon 02-05-2010 11:02 PM

ehh good idea.. but I'm stuck at my lame day job all day tomorrow and have tons of other junk to finish too.

two of the three programs are written but have a major logical error and one has an infinite loop.. both suck

Craig 02-05-2010 11:08 PM

Good luck. I can do algebra, but I'm the worlds worst programmer.

TheDon 02-12-2010 09:08 AM

Quote:

Originally Posted by Brian Carlton (Post 2399641)
(3X)(X)=300

3X^2=300

X^2=100

X=10


Rectangle is 30 x 10.

ah ha.. mhmmm.. yes.. why didn't I think of that before

Brian Carlton 02-12-2010 09:12 AM

Quote:

Originally Posted by TheDon (Post 2404021)
ah ha.. mhmmm.. yes.. why didn't I think of that before

...........you were too frigin tired...........

TheDon 02-12-2010 09:17 AM

correct!

now to get stuck in an infinite loop

kerry 02-12-2010 09:44 AM

Go to sleep and figure it out in your dreams.

Zeus 02-12-2010 10:00 AM

Lol @ tonk, Brian, Craig.

Triple post within minutes, all correct. :D

Now that you are warmed up, here is a real challenge.

http://www.youtube.com/watch?v=izrNv4nMxAg

Think it's possible? Without CGI that is.

Vitals

Mercedes SLS AMG
420 kW/571 hp peak output, 650 Nm of torque
1620 kg
0 to 100 km/h in 3.8 seconds and has a top speed of 317 km/h

Tunnel appears approx. 30 feet in circumference, length is tough to determine.

Downdraft, centrifugal forces...

Possible? Get the scientific calculators out...

Brian Carlton 02-12-2010 10:12 AM

Quote:

Originally Posted by Zeus (Post 2404046)
Lol @ tonk, Brian, Craig.

Triple post within minutes, all correct. :D

Now that you are warmed up, here is a real challenge.

http://www.youtube.com/watch?v=izrNv4nMxAg

Think it's possible? Without CGI that is.

Vitals

Mercedes SLS AMG
420 kW/571 hp peak output, 650 Nm of torque
1620 kg
0 to 100 km/h in 3.8 seconds and has a top speed of 317 km/h

Tunnel appears approx. 30 feet in circumference, length is tough to determine.

Downdraft, centrifugal forces...

Possible? Get the scientific calculators out...

It's absolutely impossible to generate more downdraft than the weight of the car without some type of wing attached to it.

Therefore, the only way it works is if the tunnel has an arc that basically follows the curvature of the earth.

The problem with this solution is the difficulty of the timing in getting to this arc. If the arc starts too early, the vehicle goes airborne.

The second problem is the fact that the conventional curve of the tunnel (to the right) would need to reverse itself (to the left) at the precise point where the vehicle reaches the apex and is upside down.

A tunnel could be constructed to achieve this result, but there would be many trashed vehicles and dead drivers until the timing was mastered.


I get a radius of the arc of 2611 feet if the vehicle is moving at maximum speed. The forces generated would just barely match it's weight at that radius. The rather large number is somewhat surprising............maybe someone else can verify it.


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