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  #1  
Old 01-27-2011, 04:06 PM
TheDon's Avatar
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simple physics question

I'm stuck on a homework problem.

Here is what I have so far


= -17 degrees counterclockwise from the positive x axis

= 30 meters


= 87 degrees counterclockwise from the positive x axis


= 20 meters



I'm having issues getting

in terms of ______degrees counterclockwise from the positive x axis


and



the magnitude


"m" was for meters


Last edited by TheDon; 01-27-2011 at 10:31 PM.
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  #2  
Old 01-27-2011, 05:00 PM
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what is 'm' ? ?

Begin by breaking A into its components using sine and cosine... sound familiar? make a quick sketch.
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  #3  
Old 01-27-2011, 05:14 PM
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Quote:
Originally Posted by TheDon View Post

= -17 degrees...
What does that mean?
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  #4  
Old 01-27-2011, 05:17 PM
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I am assuming we're finding the angle of the resultant of A + B and that 'm' was a typo for the angle of B from the x-axis.

so here are the components I got:

A = <28.7i - 8.77j>

B= <1.047i + 20.0j>

Now add the vectors together. keeping the units separate.
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  #5  
Old 01-27-2011, 05:19 PM
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the magnitude of a vector (the one in the absolute value sign) is sqrt(i^2 + j^2 +k^2)

using the coefficients of each unit.


---I am not going any further until you clean up the first post..
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  #6  
Old 01-27-2011, 05:49 PM
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I fixed my first post.

I tried to get the magnitude of by taking the magnitude of A and B.. squaring both, adding together and taking the square root of the result

i.e sqrt((30)^2+(20)^2))... but that is not the correct answer.

For theta I am also confused.. I looked at my notes but the method used there isn't giving me a correct answer.

If it helps here are the vectors

A = (29m)x + (-9m)y

B = (1.0m) + (20m)y
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  #7  
Old 01-27-2011, 05:50 PM
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I'm waiting for the "simple" part . . .
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  #8  
Old 01-27-2011, 05:55 PM
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I'm going with "6".
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  #9  
Old 01-27-2011, 05:57 PM
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I'm thinking 33?
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  #10  
Old 01-27-2011, 06:00 PM
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Quote:
Originally Posted by MTI View Post
I'm waiting for the "simple" part . . .
it's just vectors?
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  #11  
Old 01-27-2011, 07:42 PM
Craig
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Quote:
Originally Posted by TheDon View Post
I fixed my first post.

I tried to get the magnitude of by taking the magnitude of A and B.. squaring both, adding together and taking the square root of the result

i.e sqrt((30)^2+(20)^2))... but that is not the correct answer.

For theta I am also confused.. I looked at my notes but the method used there isn't giving me a correct answer.

If it helps here are the vectors

A = (29m)x + (-9m)y

B = (1.0m) + (20m)y
The magnitude method you used only works for right angles.

If you add the vectors you get

30x + 11y

30^2 + 11^2 = 31.95^2

To get the angle:

ArcTan(11/30) = 20.136 Deg
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  #12  
Old 01-27-2011, 08:50 PM
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Quote:
Originally Posted by TheDon View Post
I fixed my first post....
You did?

I am now thirty years removed from engineering school, so maybe I am out of date, but I have never seen notation of this sort:
Quote:
Originally Posted by TheDon View Post

= -17 degrees counterclockwise from the positive x axis
And I still don't know what "m" is.
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  #13  
Old 01-27-2011, 08:53 PM
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Vector addition of A + B. I never went to engineering school. But that's what they told us botanists when I was in school a half-century ago and then we pulled out the log-log slide rule ......
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  #14  
Old 01-27-2011, 08:57 PM
Craig
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He's saying that vector A has a magnitude of 30 meters and an angle of -17 degrees;

Vector B has a magnitude of 20 meters and an angle of 87 degrees.

I'm not sure what symbols he was trying to type.
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  #15  
Old 01-27-2011, 09:25 PM
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Roger Murdock: Flight 2-0-9'er, you are cleared for take-off.
Captain Oveur: Roger!
Roger Murdock: Huh?
Tower voice: L.A. departure frequency, 123 point 9'er.
Captain Oveur: Roger!
Roger Murdock: Huh?
Victor Basta: Request vector, over.
Captain Oveur: What?
Tower voice: Flight 2-0-9'er cleared for vector 324.
Roger Murdock: We have clearance, Clarence.
Captain Oveur: Roger, Roger. What's our vector, Victor?
Tower voice: Tower's radio clearance, over!
Captain Oveur: That's Clarence Oveur. Over.
Tower voice: Over.
Captain Oveur: Roger.
Roger Murdock: Huh?
Tower voice: Roger, over!
Roger Murdock: What?
Captain Oveur: Huh?
Victor Basta: Who?

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