I have replaced both tie rods (driver's and paasenger's side -the whole asembly on both sides) on my '83 240D and am wondering what the torque specs are for the nuts on the inner and outter ends.

I am also in the process tonight of doing the same on my '95 300D and have the same question for that car too.

Anyone have this info???

Thanks!

__________________
'95 E300D ("Tank") - 231,000 miles
'79 240D ("Biscuit") - 197,250 miles (Sold)
'83 240D ("Ding-Ding") - 217,000 miles (Death by deer)
______________________________________

"Back off, man. I’m a scientist” ~ Peter Venkman

Partially answered my own question. My manual states the following for the '95 300D:

Self-locking nut torque:
M10x1 = 35 Nm
M12x1 = 50 Nm

I grabbed my calipers and measured the threaded ends of my new tie rod and got 10 mm in diameter and 1 mm pitch - so I'll go with 35 Nm (or 25.8 foot pounds).


I think I read somewhere else that the torque for my '83 240d was also 35 Nm.

__________________
'95 E300D ("Tank") - 231,000 miles
'79 240D ("Biscuit") - 197,250 miles (Sold)
'83 240D ("Ding-Ding") - 217,000 miles (Death by deer)
______________________________________

"Back off, man. I’m a scientist” ~ Peter Venkman