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Electrical voltage and wattage question
I light I have uses a 200W 19.7 volt halogen. The bulb that was in it was blown and I wanted to see if the lamp worked at all. I put a 20W 12v bulb in it and it worked fine. I saw that I had a 50w 12v bulb and figured that 50 is closer to 200 than 20 so that would be better. I put it in and the bulb blew. Figured may be it was a bad bulb so I tried another one and it blew. Now I am some what scared of putting in the 200W 19.7 volt bulb that I have on order.
Can someone here give me peace of mind and explain how this wattage/voltage thing works? Why does a 20W work fine but not a 50w? |
I'll give it a shot. We are talking about voltage (V), current (I) and wattage (W); the governing equation is:
I * V = W Therefore, to determine the current used by a 50W, 12V bulb: I = W/V I = 50/12 I = 4.2 amps The resistance through that bulb is: R = V/I R = 12/4.2 R = 2.9 ohms. Now if we put that bulb in a 19.7 V lamp: I = V/R I = 19.7/2.9 I = 6.8 amps So, you are putting 6.8 amps through a bulb that was designed for 4.2 amps; and it blew. There is no reason to think the correct bulb will blow. Does that help? |
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voltage is E not V lol :D
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You cannot substitute lower voltage bulbs and expect them to survive more than a few minutes. Think about the vehicle. If the voltage regulator decides to go AWOL and offer up 17V, all the bulbs in the vehicle shine brightly, but their life is decidedly limited. Same deal with your 12V bulb. |
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:eek: |
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And to think they used to teach Ohms law in seventh grade Science!
http://www.aoce.com/images/EV_EFUNm0...wFormulas2.jpg |
Great Chart!
BB,
Thanks. Mayhaps, we should affix it as a tag to all Electrical consumers WW ? |
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Recently, two friends of mine named Stan (one electrical, one mechanical) were working together on a consulting gig for several weeks. They called themselves "sparkystan" and "mechanicstan" to avoid confusion (you would have to meet these guys to fully appreciate it). |
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