
11-12-2010, 12:03 PM
|
Banned
|
|
Join Date: May 2002
Location: Blue Point, NY
Posts: 25,396
|
|
Quote:
Originally Posted by Honus
Sorry to come to this discussion so late, but I am confused.
Do we agree that the distance from the observer to the boat is the hypotenuse?
And that the calculation goes as follows:
distance = 300/sin(15.9) = 1095' ?
Is that correct?
|
Correct.
|