Quote:
Originally Posted by Forced Induction
With an intercooler the air density is increased, so that means less boost should be used since you're flowing more air psi-for-psi. 
10psi with a decent intercooler flows the same volume and mass of air as 15psi with no intercooler. |
A rather general statement, but a lot of things work into the P=V/T equation there Lance.
If the intercooler is dropping the temperature by 1/3, then yes in theory the pressure will also be lower by 1/3 for the same mass. However, this also depends somewhat on where the pressure measurement is taken as the pressure pre-intercooler will be higher than post-intercooler due to the temperature drop and to the restriction that the intercooler might pose to airflow. You're also making a pretty big assumption that the temperature will drop by 1/3.
Now I beileve that the previous posts are providing information regarding how much more boost the enigne can handle at cooler temperatures (and thus add more fuel) rather than how to calculate P=V/T