Ken,

The * should have been a /. So 5650/(t2/5.825)^3)/(5650/(t1/5.825)^3 BUT, I actually took time to read the whole page I posted and the initial post. It makes more sense to me now but doesn't help you one bit. The formulae are intended for use with 1/4 mile times, not 0-60 times. Seems like the reason 1/4 mile times are used is because the distance travelled is known.

I went to the library last night to try and figure out this problem. No luck but I did learn something:

One horsepower is defined as the ability to move 33,000 pounds one foot in one minute. This might be why I can't find a formula which gives us hp for 0-60 times.

I also figured out a coupla things that might be interesting to note. Using:

Initial velocity = 0
Final velocity = (6*5280ft)/3600s=88ft/s

then divide by 17.4s yields 5.05ft/s

Second set of figures gave an acceleration of 6.77ft/s.

This means average velocity for the original engine was (17.4/2)*5.05 = 43.9ft/s

compared to

(13/2)*6.77 = 44ft/s!

The difference in average velocity is not much, so yeah, I don't think you have 350hp! So can we assume that it takes 150hp to move 5650lbs 763.86 feet in 17.4 seconds? If so, how many hp does it take to move 5650lbs 572 feet in 13 seconds? I'm having some difficulty here, someone jump in please?

Hmmm... Kuan (shoulda stayed in skule)