Here is how you do it. First you have these rules.

P -> Q is false only once, when P is True and Q is false.

P & Q is true only once, when both P and Q are true.

P v Q is false only once, when both P and Q are false, or, only one variable needs to be true in order for the statement to be true.

P <-> Q is true only when both P, Q, have the same values. ie., when P and Q are True then the <-> is true.

So first, fill in underneath your P, Q, and R, your given values. So

Then you fill in the values for the operators -> and v.

So

p -> ~p is false, so fill in F under the conditional arrow.

r is true, so as per the rule, that a disjunction only needs one variable true to be true, fill in T underneath the v sign.

So the statement is True.

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