Quote:
Originally Posted by jt20
personally, to simplify this problem, I would gather all the terms by multiplying through.
then change all the uncommon identities (the ones you don't know off the top of your head) to the three common identities (sin cos tan)
then diff.
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well ive got the differential values of all 6 trig functions.
I multipled them through but im just confused what to do with the right side
with the -csc^2@-csc@cot^2@ result
-csc^2@ is equivelent to -1-cot^2@ [ csc^2@ - cot^2@ = 1]