just updating from our PM; I didn't take into account the lack of calculator:
Quote:
I don't know how you would use pythg... please enlighten me.
Given the table, I would use the identity of tan.
tan(15.9)=sin(15.9)/cos(15.9)
you want to solve for x so: 300/x = sin(15.9)/cos(15.9)
then, the values for sin and cos are on the table.
then use pythg once you have x: x^2 + 300^2 = hyp^2
hyp = distance to the boat.
you could make a really close estimate at that point. the number I posted was from me using a calculator.
x=1046.4 hyp= 1088.6 using 16* on the table
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thank cmac for the correction!