Quote:
Originally Posted by Honus
Sorry to come to this discussion so late, but I am confused.
Do we agree that the distance from the observer to the boat is the hypotenuse?
And that the calculation goes as follows:
distance = 300/sin(15.9) = 1095' ?
Is that correct?
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So I would take 300/(.2756)(15.9)
That actually was the original question.