Quote:
Originally Posted by layback40
Not true !!
You have not calculated the average speed !!
If we assume constant acceleration, we can use one of the equations Botnst links to ;
Distance = initial velocity X time + 1/2 X acceleration X time squared.
If acceleration varies, the area under a velocity/ time graph would give you the answer.
BC is correct in converting to compatible units.
velocity in ft/sec , time in sec , distance in ft.
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If Ah-Kay made a mistake, how did he come to the correct answer?
There is no graph of any sort to consider just the simple case posed by the OP. Averaging the speed is perfectly valid in this case.