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Old 04-06-2005, 12:28 AM
Arthur Dalton Arthur Dalton is offline
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Join Date: Aug 1999
Location: Florida / N.H.
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Incorrect..
Look at the schematic and you will see the chain of power flow. It is ign sw. ,to K38, , to NSS, to starter sol.
You have simply jumpered the K38 part of the chain. This is a series circuit and you have just jumpered one part of it.
You will notice in the right side of the schematic that the CDN versions simply do what you have done cuz they do not have ATA.
What you want to do is jumper R50 an 50 at NSS... or look there for power from ignition start switch..

Last edited by Arthur Dalton; 04-06-2005 at 12:42 AM.
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