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#1
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question
ok so how do I find the perimeter of a rectangle if area is given and the ratio W x L is given..
like area=300 and the ratio is 3:1 |
#2
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Quote:
let 3x = W L x W -=area , so x X 3x = 300 3x squared = 300 therefore x squared = 100 therefore x=10 therefore L=10 W=30 therefore L+W+L+W = perimeter so 80 = perimeter (i think )
__________________
"The law, in its majestic equality, forbids the rich as well as the poor to sleep under bridges, to beg in the streets, and to steal bread." |
#3
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(3X)(X)=300
3X^2=300 X^2=100 X=10 Rectangle is 30 x 10. |
#4
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L = 3W
P = 2L+2W = 6W + 2W = 8W A = L*W = 3W*W = 3W^2 If A=300, W=10, L=30, P=80 |
#5
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Great minds....
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#6
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im too frigin tired.. im dealing with damn infinite loops and logical errors and cant think
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#7
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Get a couple of hours of sleep and work while you're awake.
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#8
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ehh good idea.. but I'm stuck at my lame day job all day tomorrow and have tons of other junk to finish too.
two of the three programs are written but have a major logical error and one has an infinite loop.. both suck |
#9
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Good luck. I can do algebra, but I'm the worlds worst programmer.
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#10
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ah ha.. mhmmm.. yes.. why didn't I think of that before
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#11
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...........you were too frigin tired...........
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#12
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correct!
now to get stuck in an infinite loop |
#13
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Go to sleep and figure it out in your dreams.
__________________
1977 300d 70k--sold 08 1985 300TD 185k+ 1984 307d 126k--sold 8/03 1985 409d 65k--sold 06 1984 300SD 315k--daughter's car 1979 300SD 122k--sold 2/11 1999 Fuso FG Expedition Camper 1993 GMC Sierra 6.5 TD 4x4 1982 Bluebird Wanderlodge CAT 3208--Sold 2/13 |
#14
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Lol @ tonk, Brian, Craig.
Triple post within minutes, all correct. Now that you are warmed up, here is a real challenge. http://www.youtube.com/watch?v=izrNv4nMxAg Think it's possible? Without CGI that is. Vitals Mercedes SLS AMG 420 kW/571 hp peak output, 650 Nm of torque 1620 kg 0 to 100 km/h in 3.8 seconds and has a top speed of 317 km/h Tunnel appears approx. 30 feet in circumference, length is tough to determine. Downdraft, centrifugal forces... Possible? Get the scientific calculators out...
__________________
Chris 2007 E550 4Matic - 61,000 Km - Iridium Silver, black leather, Sport package, Premium 2 package 2007 GL450 4Matic - 62,000 Km - Obsidian Black Metallic, black leather, all options 1998 E430 - sold 1989 300E - 333,000 Km - sold 1977 280E - sold 1971 250 - retired "And a frign hat. They gave me a hat at the annual benefits meeting. I said. how does this benefit me. I dont have anything from the company.. So they gave me a hat." - TheDon |
#15
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Quote:
Therefore, the only way it works is if the tunnel has an arc that basically follows the curvature of the earth. The problem with this solution is the difficulty of the timing in getting to this arc. If the arc starts too early, the vehicle goes airborne. The second problem is the fact that the conventional curve of the tunnel (to the right) would need to reverse itself (to the left) at the precise point where the vehicle reaches the apex and is upside down. A tunnel could be constructed to achieve this result, but there would be many trashed vehicles and dead drivers until the timing was mastered. I get a radius of the arc of 2611 feet if the vehicle is moving at maximum speed. The forces generated would just barely match it's weight at that radius. The rather large number is somewhat surprising............maybe someone else can verify it. Last edited by Brian Carlton; 02-12-2010 at 10:34 AM. |
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