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  #16  
Old 09-17-2010, 11:35 PM
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It is unlikely that the result of distributing then differentiation will result in something that is accepted. The difference between "not the simplest" and that is an ocean.

But multiple answers are likely correct, because this is a trigonometric expression. There are many equivalent, equally simple ways to represent many such expressions. Makes grading quite difficult. Just because you've never seen or even conceived of an answer does not automatically make it wrong.

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  #17  
Old 09-17-2010, 11:40 PM
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Quote:
Originally Posted by Matt L View Post
It is unlikely that the result of distributing then differentiation will result in something that is accepted.

I only suggested that as the next step... not the end result.
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  #18  
Old 09-17-2010, 11:56 PM
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Originally Posted by jt20 View Post
I only suggested that as the next step... not the end result.
The next step is far easier if you apply the product rule, rather than going to the basic principles of distributing, differentiating, and factoring.

Applying the product rule leaves the result partially factored. That's why it is used.
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  #19  
Old 09-18-2010, 12:10 AM
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Quote:
Originally Posted by Matt L View Post
The next step is far easier if you apply the product rule, rather than going to the basic principles of distributing, differentiating, and factoring.

Applying the product rule leaves the result partially factored. That's why it is used.

Thank you for the correction. I lost track there.
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  #20  
Old 09-18-2010, 12:14 AM
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I've, uh, done a bit of calculus in my day.
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  #21  
Old 09-18-2010, 12:28 AM
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Originally Posted by TheDon View Post
ok

I will use @ for theta

csc@(1-csc@^2) + (@ + cot@)(-csc@cot@)

then I get confused what to do with the right side.

there is a mistake here. Either your substitution or diff'ing missed something.

the derivative of theta wrt theta is 1. So in these parentheses you should get a -1 and +1...they cancel

my final was y'= -@*cos@/sin^2@ - 2*cos^2@/sin^3@

I can show algebra if you need it.. just lazy right now.

do you have Maple?

Last edited by jt20; 09-18-2010 at 01:32 AM. Reason: paste issues
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  #22  
Old 09-18-2010, 12:31 AM
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Originally Posted by Matt L View Post
I've, uh, done a bit of calculus in my day.

It makes you a better person.

I'm sure Buddha or Lao-Tzu would agree.
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  #23  
Old 09-18-2010, 12:40 AM
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Originally Posted by jt20 View Post
there is a mistake here. Either your substitution or diff'ing missed something.

it isn't really a mistake.. just a poor choice.

I think you have something equivalent... but keep the cot form and you should be able to put your two 'sides' together.
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  #24  
Old 09-18-2010, 01:22 AM
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well the form is gf'+fg'

-csc^2@ is the differention of cot@
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  #25  
Old 09-18-2010, 01:35 AM
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Have you tried www.wolframalpa.com dont forget to click on show steps
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  #26  
Old 09-18-2010, 01:38 AM
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This is the Wiley Plus online math stuff is it? Just curious.

Also, what major are you again? I took a pre-calc/trig course that I should not have...I regret it. A LOT.
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  #27  
Old 09-18-2010, 01:39 AM
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y=csc@*(@+cot@)

y'=-@*csc@cot@*(@+cot@)+csc@*[1+(-1-cot^2@)]

=-@*1/sin@*1/tan@ - 2/(sin@*tan^2@)

=-@*cos@/sin^2@ - 2*cos^2@/sin^3@
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  #28  
Old 09-18-2010, 01:43 AM
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Quote:
Originally Posted by layback40 View Post
Have you tried www.wolframalpa.com dont forget to click on show steps

wolframalpha. com


confusing if you can't do it by hand first.

its great for checking answers, not for doing algebra.
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  #29  
Old 09-18-2010, 01:53 AM
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Quote:
Originally Posted by TheDon View Post
well the form is gf'+fg'

-csc^2@ is the differention of cot@

remember the identity you gave in the earlier post?

use that to give each 'side' a cot function. This will allow you to combine them.

I also checked that answer I supplied with software
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  #30  
Old 09-18-2010, 01:56 AM
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here is a link to layback's suggestion

it shows some other variations

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