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#7
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Quote:
But, here goes: Let's work in feet/second, which is easier. The acceleration of the 300D is 6 ft./sec² (0-60 in 15 sec.) The distance that you are interested in is 2640 feet. The formula for velocity is: V²=2AS. A is acceleration, S is distance. So your velocity at 1/2 mile is 178 ft./sec. or 121 mph. HOWEVER: The 300D cannot sustain an acceleration of 6 ft./sec² between the speeds of 60 mph and 121 mph. This is due to the very strong effect of wind resistance on the body. The vehicle would never reach 121 mph within 1/2 mile. Hell, it wouldn't reach 121 mph in 5 miles. ![]() The actual answer to your question can only be acheived with a stopwatch.
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