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#1
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Quote:
Just trying to understand....
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14 E250 Bluetec 4Matic "Sinclair", Palladium Silver on Black, 159k miles 06 E320 CDI "Rutherford", Black on Tan, 178k mi, Stage 1 tune, tuned TCU 91 300D "Otis", Smoke Silver on Tan, 145k mi, wastegate conversion, ALDA delete 19 Honda CR-V EX 75k mi Fourteen other MB's owned and sold 1961 Very Tolerant Wife |
#2
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For example, let's say system "X" contains ten quarts of fluid (ten is convenient here for the math), and let's say that between each exchange of one quart, the "old" fluid stays "old" and the "new" stays "new." Change 1) - remove one quart of mixed fluid, replace with one quart of newChange 2) - remove one quart of mixed fluid, replace with one quart of newChange 3) - remove one quart of mixed fluid, replace with one quart of new... and so on, ending up with these amounts after each change: Change 4) 6.6 old, 3.4 new Change 5) 5.9 old, 4.1 new Change 6) 5.3 old, 4.7 new Change 7) 4.8 old, 5.2 new Change 8) 4.3 old, 5.7 new Change 9) 3.9 old, 6.1 new Change 10) 3.5 old, 6.5 new So, after ten changes using a total of 10.0 quarts, you only end up with only 6.5 quarts of new fluid, whereas if you'd changed it out in one session, you'd have 10.0 quarts of new fluid. It would take a long time and many changes to even approach a total changeout. Yes, the proportion of changeout on the real system we're talking about would be higher and you'd approach the asymptote more quickly, but the point is still the same. Put another way, one job done halfway, plus another job done halfway doesn't equal one job done completely. |
#3
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John
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John HAUL AWAY, OR CRUSHED CARS!!! HELP ME keep the cars out of the crusher! A/C Thread "as I ride with my a/c on... I have fond memories of sweaty oily saturdays and spewing R12 into the air. THANKS for all you do! My drivers: 1987 190D 2.5Turbo 1987 560SL convertible 1987 190D 2.5-5SPEED!!! ![]() 1987 300TD 2005 Dodge Sprinter 2500 158"WB 1994GMC 2500 6.5Turbo truck... I had to put the ladder somewhere! |
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