Quote:
Originally Posted by buffa98
So another question that sticks in my mind uses the angle of the sun and the length of a shadow cast from a flag pole. seeing that I have the Hyp angle and length ,I would use the cos to find the short leg?
which in this case would be the height of the flagpole?
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given: hyp = h ; theta= b
sin(b)=Opposite/h ==> sin(b) * h =opposite
I am assuming theta is the angle you're talking about. The sun is at the top right. "the short leg" is 'opposite'.
if the short leg is "adjacent"
cos(b) = adjacent/h ==> cos(b) * h = adjacent
11-12-2010, 04:58 PM
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