Trigonometry Question - PeachParts Mercedes-Benz Forum

jt20 · #1 11-12-2010, 04:58 PM

Quote:

Originally Posted by buffa98

So another question that sticks in my mind uses the angle of the sun and the length of a shadow cast from a flag pole. seeing that I have the Hyp angle and length ,I would use the cos to find the short leg?

which in this case would be the height of the flagpole?

given: hyp = h ; theta= b

sin(b)=Opposite/h ==> sin(b) * h =opposite

I am assuming theta is the angle you're talking about. The sun is at the top right. "the short leg" is 'opposite'.

if the short leg is "adjacent"

cos(b) = adjacent/h ==> cos(b) * h = adjacent

buffa98 · #2 11-12-2010, 05:08 PM

Thank you all for the help.

Jt20 that picture will be filed. That is the piece of info I needed. I should not a have an issue if I need to take this thing over.